2(s-3)+5=4(s-1)

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Solution for 2(s-3)+5=4(s-1) equation:


Simplifying
2(s + -3) + 5 = 4(s + -1)

Reorder the terms:
2(-3 + s) + 5 = 4(s + -1)
(-3 * 2 + s * 2) + 5 = 4(s + -1)
(-6 + 2s) + 5 = 4(s + -1)

Reorder the terms:
-6 + 5 + 2s = 4(s + -1)

Combine like terms: -6 + 5 = -1
-1 + 2s = 4(s + -1)

Reorder the terms:
-1 + 2s = 4(-1 + s)
-1 + 2s = (-1 * 4 + s * 4)
-1 + 2s = (-4 + 4s)

Solving
-1 + 2s = -4 + 4s

Solving for variable 's'.

Move all terms containing s to the left, all other terms to the right.

Add '-4s' to each side of the equation.
-1 + 2s + -4s = -4 + 4s + -4s

Combine like terms: 2s + -4s = -2s
-1 + -2s = -4 + 4s + -4s

Combine like terms: 4s + -4s = 0
-1 + -2s = -4 + 0
-1 + -2s = -4

Add '1' to each side of the equation.
-1 + 1 + -2s = -4 + 1

Combine like terms: -1 + 1 = 0
0 + -2s = -4 + 1
-2s = -4 + 1

Combine like terms: -4 + 1 = -3
-2s = -3

Divide each side by '-2'.
s = 1.5

Simplifying
s = 1.5

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