2(s+5/2s+20)=48(2)

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Solution for 2(s+5/2s+20)=48(2) equation: 



2(s+5/2s+20)=48(2)

We move all terms to the left:

2(s+5/2s+20)-(48(2))=0



Domain of the equation: 2s+20)!=0

s∈R



determiningTheFunctionDomain
2(s+5/2s+20)-482=0

We multiply parentheses

2s+10s+40-482=0

We add all the numbers together, and all the variables

12s-442=0

We move all terms containing s to the left, all other terms to the right

12s=442

s=442/12

s=36+5/6

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