2(r-+3)=4(r-+10)

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Solution for 2(r-+3)=4(r-+10) equation: 



2(r-+3)=4(r-+10)

We move all terms to the left:

2(r-+3)-(4(r-+10))=0

We add all the numbers together, and all the variables

2(+r)-(4(+r))=0

We multiply parentheses

2r-(4(+r))=0



We calculate terms in parentheses: -(4(+r)), so:

4(+r)

We multiply parentheses

4r

Back to the equation:

-(4r)



We add all the numbers together, and all the variables

-2r=0

r=0/-2

r=0

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