2(r+5)-32=4(r-1)

Solution for 2(r+5)-32=4(r-1) equation:

2(r+5)-32=4(r-1)

We move all terms to the left:

2(r+5)-32-(4(r-1))=0

We multiply parentheses

2r-(4(r-1))+10-32=0


We calculate terms in parentheses: -(4(r-1)), so:

4(r-1)

We multiply parentheses

4r-4

Back to the equation:

-(4r-4)


We add all the numbers together, and all the variables

2r-(4r-4)-22=0

We get rid of parentheses

2r-4r+4-22=0

We add all the numbers together, and all the variables

-2r-18=0

We move all terms containing r to the left, all other terms to the right

-2r=18

r=18/-2

r=-9