2(r+3)=4(r+4)

Solution for 2(r+3)=4(r+4) equation:

Simplifying
2(r + 3) = 4(r + 4)

Reorder the terms:
2(3 + r) = 4(r + 4)
(3 * 2 + r * 2) = 4(r + 4)
(6 + 2r) = 4(r + 4)

Reorder the terms:
6 + 2r = 4(4 + r)
6 + 2r = (4 * 4 + r * 4)
6 + 2r = (16 + 4r)

Solving
6 + 2r = 16 + 4r

Solving for variable 'r'.

Move all terms containing r to the left, all other terms to the right.

Add '-4r' to each side of the equation.
6 + 2r + -4r = 16 + 4r + -4r

Combine like terms: 2r + -4r = -2r
6 + -2r = 16 + 4r + -4r

Combine like terms: 4r + -4r = 0
6 + -2r = 16 + 0
6 + -2r = 16

Add '-6' to each side of the equation.
6 + -6 + -2r = 16 + -6

Combine like terms: 6 + -6 = 0
0 + -2r = 16 + -6
-2r = 16 + -6

Combine like terms: 16 + -6 = 10
-2r = 10

Divide each side by '-2'.
r = -5

Simplifying
r = -5