2(r+3)=3(4+r)-11

Solution for 2(r+3)=3(4+r)-11 equation:

2(r+3)=3(4+r)-11

We move all terms to the left:

2(r+3)-(3(4+r)-11)=0

We add all the numbers together, and all the variables

2(r+3)-(3(r+4)-11)=0

We multiply parentheses

2r-(3(r+4)-11)+6=0


We calculate terms in parentheses: -(3(r+4)-11), so:

3(r+4)-11

We multiply parentheses

3r+12-11

We add all the numbers together, and all the variables

3r+1

Back to the equation:

-(3r+1)


We get rid of parentheses

2r-3r-1+6=0

We add all the numbers together, and all the variables

-1r+5=0

We move all terms containing r to the left, all other terms to the right

-r=-5

r=-5/-1

r=+5