2(r+3)=12

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Solution for 2(r+3)=12 equation: 



2(r+3)=12

We move all terms to the left:

2(r+3)-(12)=0

We multiply parentheses

2r+6-12=0

We add all the numbers together, and all the variables

2r-6=0

We move all terms containing r to the left, all other terms to the right

2r=6

r=6/2

r=3

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