2(r+2)+3(-2+2r)=-34

Solution for 2(r+2)+3(-2+2r)=-34 equation:

Simplifying
2(r + 2) + 3(-2 + 2r) = -34

Reorder the terms:
2(2 + r) + 3(-2 + 2r) = -34
(2 * 2 + r * 2) + 3(-2 + 2r) = -34
(4 + 2r) + 3(-2 + 2r) = -34
4 + 2r + (-2 * 3 + 2r * 3) = -34
4 + 2r + (-6 + 6r) = -34

Reorder the terms:
4 + -6 + 2r + 6r = -34

Combine like terms: 4 + -6 = -2
-2 + 2r + 6r = -34

Combine like terms: 2r + 6r = 8r
-2 + 8r = -34

Solving
-2 + 8r = -34

Solving for variable 'r'.

Move all terms containing r to the left, all other terms to the right.

Add '2' to each side of the equation.
-2 + 2 + 8r = -34 + 2

Combine like terms: -2 + 2 = 0
0 + 8r = -34 + 2
8r = -34 + 2

Combine like terms: -34 + 2 = -32
8r = -32

Divide each side by '8'.
r = -4

Simplifying
r = -4