2(q-3)+-8=2

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Solution for 2(q-3)+-8=2 equation: 



2(q-3)+-8=2

We move all terms to the left:

2(q-3)+-8-(2)=0

determiningTheFunctionDomain
2(q-3)-8-2+=0

We add all the numbers together, and all the variables

2(q-3)=0

We multiply parentheses

2q-6=0

We move all terms containing q to the left, all other terms to the right

2q=6

q=6/2

q=3

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