2(n-8)=4(-2n-1)

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Solution for 2(n-8)=4(-2n-1) equation: 



2(n-8)=4(-2n-1)

We move all terms to the left:

2(n-8)-(4(-2n-1))=0

We multiply parentheses

2n-(4(-2n-1))-16=0



We calculate terms in parentheses: -(4(-2n-1)), so:

4(-2n-1)

We multiply parentheses

-8n-4

Back to the equation:

-(-8n-4)



We get rid of parentheses

2n+8n+4-16=0

We add all the numbers together, and all the variables

10n-12=0

We move all terms containing n to the left, all other terms to the right

10n=12

n=12/10

n=1+1/5

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