2(n-4)=-4(n-3)-4n

Solution for 2(n-4)=-4(n-3)-4n equation:

2(n-4)=-4(n-3)-4n

We move all terms to the left:

2(n-4)-(-4(n-3)-4n)=0

We multiply parentheses

2n-(-4(n-3)-4n)-8=0


We calculate terms in parentheses: -(-4(n-3)-4n), so:

-4(n-3)-4n

We add all the numbers together, and all the variables

-4n-4(n-3)

We multiply parentheses

-4n-4n+12

We add all the numbers together, and all the variables

-8n+12

Back to the equation:

-(-8n+12)


We get rid of parentheses

2n+8n-12-8=0

We add all the numbers together, and all the variables

10n-20=0

We move all terms containing n to the left, all other terms to the right

10n=20

n=20/10

n=2