2(n-4)-3(n-2)=4(a+1)+4

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Solution for 2(n-4)-3(n-2)=4(a+1)+4 equation:


Simplifying
2(n + -4) + -3(n + -2) = 4(a + 1) + 4

Reorder the terms:
2(-4 + n) + -3(n + -2) = 4(a + 1) + 4
(-4 * 2 + n * 2) + -3(n + -2) = 4(a + 1) + 4
(-8 + 2n) + -3(n + -2) = 4(a + 1) + 4

Reorder the terms:
-8 + 2n + -3(-2 + n) = 4(a + 1) + 4
-8 + 2n + (-2 * -3 + n * -3) = 4(a + 1) + 4
-8 + 2n + (6 + -3n) = 4(a + 1) + 4

Reorder the terms:
-8 + 6 + 2n + -3n = 4(a + 1) + 4

Combine like terms: -8 + 6 = -2
-2 + 2n + -3n = 4(a + 1) + 4

Combine like terms: 2n + -3n = -1n
-2 + -1n = 4(a + 1) + 4

Reorder the terms:
-2 + -1n = 4(1 + a) + 4
-2 + -1n = (1 * 4 + a * 4) + 4
-2 + -1n = (4 + 4a) + 4

Reorder the terms:
-2 + -1n = 4 + 4 + 4a

Combine like terms: 4 + 4 = 8
-2 + -1n = 8 + 4a

Solving
-2 + -1n = 8 + 4a

Solving for variable 'n'.

Move all terms containing n to the left, all other terms to the right.

Add '2' to each side of the equation.
-2 + 2 + -1n = 8 + 2 + 4a

Combine like terms: -2 + 2 = 0
0 + -1n = 8 + 2 + 4a
-1n = 8 + 2 + 4a

Combine like terms: 8 + 2 = 10
-1n = 10 + 4a

Divide each side by '-1'.
n = -10 + -4a

Simplifying
n = -10 + -4a

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