2(n-3)=3(4n-2)

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Solution for 2(n-3)=3(4n-2) equation: 



2(n-3)=3(4n-2)

We move all terms to the left:

2(n-3)-(3(4n-2))=0

We multiply parentheses

2n-(3(4n-2))-6=0



We calculate terms in parentheses: -(3(4n-2)), so:

3(4n-2)

We multiply parentheses

12n-6

Back to the equation:

-(12n-6)



We get rid of parentheses

2n-12n+6-6=0

We add all the numbers together, and all the variables

-10n=0

n=0/-10

n=0

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