2(n-3)=-10(n+3)

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Solution for 2(n-3)=-10(n+3) equation: 



2(n-3)=-10(n+3)

We move all terms to the left:

2(n-3)-(-10(n+3))=0

We multiply parentheses

2n-(-10(n+3))-6=0



We calculate terms in parentheses: -(-10(n+3)), so:

-10(n+3)

We multiply parentheses

-10n-30

Back to the equation:

-(-10n-30)



We get rid of parentheses

2n+10n+30-6=0

We add all the numbers together, and all the variables

12n+24=0

We move all terms containing n to the left, all other terms to the right

12n=-24

n=-24/12

n=-2

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