2(n-1)+4n=2(2n-1)

Solution for 2(n-1)+4n=2(2n-1) equation:

2(n-1)+4n=2(2n-1)

We move all terms to the left:

2(n-1)+4n-(2(2n-1))=0

We add all the numbers together, and all the variables

4n+2(n-1)-(2(2n-1))=0

We multiply parentheses

4n+2n-(2(2n-1))-2=0


We calculate terms in parentheses: -(2(2n-1)), so:

2(2n-1)

We multiply parentheses

4n-2

Back to the equation:

-(4n-2)


We add all the numbers together, and all the variables

6n-(4n-2)-2=0

We get rid of parentheses

6n-4n+2-2=0

We add all the numbers together, and all the variables

2n=0

n=0/2

n=0