2(n-1)+2(n+2)=5

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Solution for 2(n-1)+2(n+2)=5 equation:


Simplifying
2(n + -1) + 2(n + 2) = 5

Reorder the terms:
2(-1 + n) + 2(n + 2) = 5
(-1 * 2 + n * 2) + 2(n + 2) = 5
(-2 + 2n) + 2(n + 2) = 5

Reorder the terms:
-2 + 2n + 2(2 + n) = 5
-2 + 2n + (2 * 2 + n * 2) = 5
-2 + 2n + (4 + 2n) = 5

Reorder the terms:
-2 + 4 + 2n + 2n = 5

Combine like terms: -2 + 4 = 2
2 + 2n + 2n = 5

Combine like terms: 2n + 2n = 4n
2 + 4n = 5

Solving
2 + 4n = 5

Solving for variable 'n'.

Move all terms containing n to the left, all other terms to the right.

Add '-2' to each side of the equation.
2 + -2 + 4n = 5 + -2

Combine like terms: 2 + -2 = 0
0 + 4n = 5 + -2
4n = 5 + -2

Combine like terms: 5 + -2 = 3
4n = 3

Divide each side by '4'.
n = 0.75

Simplifying
n = 0.75

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