2(n-1)+1=(n-5)+(n-2)

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Solution for 2(n-1)+1=(n-5)+(n-2) equation: 



2(n-1)+1=(n-5)+(n-2)

We move all terms to the left:

2(n-1)+1-((n-5)+(n-2))=0

We multiply parentheses

2n-((n-5)+(n-2))-2+1=0



We calculate terms in parentheses: -((n-5)+(n-2)), so:

(n-5)+(n-2)

We get rid of parentheses

n+n-5-2

We add all the numbers together, and all the variables

2n-7

Back to the equation:

-(2n-7)



We add all the numbers together, and all the variables

2n-(2n-7)-1=0

We get rid of parentheses

2n-2n+7-1=0

We add all the numbers together, and all the variables

6!=0

There is no solution for this equation

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