2(n+5)=3(n-4)+20

Solution for 2(n+5)=3(n-4)+20 equation:

2(n+5)=3(n-4)+20

We move all terms to the left:

2(n+5)-(3(n-4)+20)=0

We multiply parentheses

2n-(3(n-4)+20)+10=0


We calculate terms in parentheses: -(3(n-4)+20), so:

3(n-4)+20

We multiply parentheses

3n-12+20

We add all the numbers together, and all the variables

3n+8

Back to the equation:

-(3n+8)


We get rid of parentheses

2n-3n-8+10=0

We add all the numbers together, and all the variables

-1n+2=0

We move all terms containing n to the left, all other terms to the right

-n=-2

n=-2/-1

n=+2