2(n+4)+8n-5(2n+3)+10=3

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Solution for 2(n+4)+8n-5(2n+3)+10=3 equation:


Simplifying
2(n + 4) + 8n + -5(2n + 3) + 10 = 3

Reorder the terms:
2(4 + n) + 8n + -5(2n + 3) + 10 = 3
(4 * 2 + n * 2) + 8n + -5(2n + 3) + 10 = 3
(8 + 2n) + 8n + -5(2n + 3) + 10 = 3

Reorder the terms:
8 + 2n + 8n + -5(3 + 2n) + 10 = 3
8 + 2n + 8n + (3 * -5 + 2n * -5) + 10 = 3
8 + 2n + 8n + (-15 + -10n) + 10 = 3

Reorder the terms:
8 + -15 + 10 + 2n + 8n + -10n = 3

Combine like terms: 8 + -15 = -7
-7 + 10 + 2n + 8n + -10n = 3

Combine like terms: -7 + 10 = 3
3 + 2n + 8n + -10n = 3

Combine like terms: 2n + 8n = 10n
3 + 10n + -10n = 3

Combine like terms: 10n + -10n = 0
3 + 0 = 3
3 = 3

Add '-3' to each side of the equation.
3 + -3 = 3 + -3

Combine like terms: 3 + -3 = 0
0 = 3 + -3

Combine like terms: 3 + -3 = 0
0 = 0

Solving
0 = 0

Couldn't find a variable to solve for.

This equation is an identity, all real numbers are solutions.

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