2(n+3)=3(n-4)

Solution for 2(n+3)=3(n-4) equation:

Simplifying
2(n + 3) = 3(n + -4)

Reorder the terms:
2(3 + n) = 3(n + -4)
(3 * 2 + n * 2) = 3(n + -4)
(6 + 2n) = 3(n + -4)

Reorder the terms:
6 + 2n = 3(-4 + n)
6 + 2n = (-4 * 3 + n * 3)
6 + 2n = (-12 + 3n)

Solving
6 + 2n = -12 + 3n

Solving for variable 'n'.

Move all terms containing n to the left, all other terms to the right.

Add '-3n' to each side of the equation.
6 + 2n + -3n = -12 + 3n + -3n

Combine like terms: 2n + -3n = -1n
6 + -1n = -12 + 3n + -3n

Combine like terms: 3n + -3n = 0
6 + -1n = -12 + 0
6 + -1n = -12

Add '-6' to each side of the equation.
6 + -6 + -1n = -12 + -6

Combine like terms: 6 + -6 = 0
0 + -1n = -12 + -6
-1n = -12 + -6

Combine like terms: -12 + -6 = -18
-1n = -18

Divide each side by '-1'.
n = 18

Simplifying
n = 18