2(n+2)=4(n+1)-2n

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Solution for 2(n+2)=4(n+1)-2n equation: 



2(n+2)=4(n+1)-2n

We move all terms to the left:

2(n+2)-(4(n+1)-2n)=0

We multiply parentheses

2n-(4(n+1)-2n)+4=0



We calculate terms in parentheses: -(4(n+1)-2n), so:

4(n+1)-2n

We add all the numbers together, and all the variables

-2n+4(n+1)

We multiply parentheses

-2n+4n+4

We add all the numbers together, and all the variables

2n+4

Back to the equation:

-(2n+4)



We get rid of parentheses

2n-2n-4+4=0

We add all the numbers together, and all the variables

=0

n=0/1

n=0

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