2(n+1)=3(n-5)

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Solution for 2(n+1)=3(n-5) equation: 



2(n+1)=3(n-5)

We move all terms to the left:

2(n+1)-(3(n-5))=0

We multiply parentheses

2n-(3(n-5))+2=0



We calculate terms in parentheses: -(3(n-5)), so:

3(n-5)

We multiply parentheses

3n-15

Back to the equation:

-(3n-15)



We get rid of parentheses

2n-3n+15+2=0

We add all the numbers together, and all the variables

-1n+17=0

We move all terms containing n to the left, all other terms to the right

-n=-17

n=-17/-1

n=+17

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