2(n+1)=3(n-2)

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Solution for 2(n+1)=3(n-2) equation: 



2(n+1)=3(n-2)

We move all terms to the left:

2(n+1)-(3(n-2))=0

We multiply parentheses

2n-(3(n-2))+2=0



We calculate terms in parentheses: -(3(n-2)), so:

3(n-2)

We multiply parentheses

3n-6

Back to the equation:

-(3n-6)



We get rid of parentheses

2n-3n+6+2=0

We add all the numbers together, and all the variables

-1n+8=0

We move all terms containing n to the left, all other terms to the right

-n=-8

n=-8/-1

n=+8

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