2(n+1)-5/n+1+2

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Solution for 2(n+1)-5/n+1+2 equation: 


D( n )

n = 0

n = 0

n = 0

n in (-oo:0) U (0:+oo)

2*(n+1)-(5/n)+1+2 = 0

2*(n+1)-5*n^-1+1+2 = 0

2*(n+1)-5/n+1+2 = 0

(2*n*(n+1))/n-5/n+(1*n)/n+(2*n)/n = 0

2*n*(n+1)+1*n+2*n-5 = 0

2*n^2+2*n+n+2*n-5 = 0

2*n^2+3*n+2*n-5 = 0

2*n^2+5*n-5 = 0

2*n^2+5*n-5 = 0

2*n^2+5*n-5 = 0

DELTA = 5^2-(-5*2*4)

DELTA = 65

DELTA > 0

n = (65^(1/2)-5)/(2*2) or n = (-65^(1/2)-5)/(2*2)

n = (65^(1/2)-5)/4 or n = (-(65^(1/2)+5))/4

(n+(65^(1/2)+5)/4)*(n-((65^(1/2)-5)/4)) = 0

((n+(65^(1/2)+5)/4)*(n-((65^(1/2)-5)/4)))/n = 0

((n+(65^(1/2)+5)/4)*(n-((65^(1/2)-5)/4)))/n = 0 // * n

(n+(65^(1/2)+5)/4)*(n-((65^(1/2)-5)/4)) = 0

( n+(65^(1/2)+5)/4 )

n+(65^(1/2)+5)/4 = 0 // - (65^(1/2)+5)/4

n = -((65^(1/2)+5)/4)

( n-((65^(1/2)-5)/4) )

n-((65^(1/2)-5)/4) = 0 // + (65^(1/2)-5)/4

n = (65^(1/2)-5)/4

n in { -((65^(1/2)+5)/4), (65^(1/2)-5)/4 }

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