2(m-8)+6m=4(3m-5)

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Solution for 2(m-8)+6m=4(3m-5) equation: 



2(m-8)+6m=4(3m-5)

We move all terms to the left:

2(m-8)+6m-(4(3m-5))=0

We add all the numbers together, and all the variables

6m+2(m-8)-(4(3m-5))=0

We multiply parentheses

6m+2m-(4(3m-5))-16=0



We calculate terms in parentheses: -(4(3m-5)), so:

4(3m-5)

We multiply parentheses

12m-20

Back to the equation:

-(12m-20)



We add all the numbers together, and all the variables

8m-(12m-20)-16=0

We get rid of parentheses

8m-12m+20-16=0

We add all the numbers together, and all the variables

-4m+4=0

We move all terms containing m to the left, all other terms to the right

-4m=-4

m=-4/-4

m=1

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