2(m-3)=4(m+1)

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Solution for 2(m-3)=4(m+1) equation: 



2(m-3)=4(m+1)

We move all terms to the left:

2(m-3)-(4(m+1))=0

We multiply parentheses

2m-(4(m+1))-6=0



We calculate terms in parentheses: -(4(m+1)), so:

4(m+1)

We multiply parentheses

4m+4

Back to the equation:

-(4m+4)



We get rid of parentheses

2m-4m-4-6=0

We add all the numbers together, and all the variables

-2m-10=0

We move all terms containing m to the left, all other terms to the right

-2m=10

m=10/-2

m=-5

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