2(m-19)=4(m+1)-18

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Solution for 2(m-19)=4(m+1)-18 equation: 



2(m-19)=4(m+1)-18

We move all terms to the left:

2(m-19)-(4(m+1)-18)=0

We multiply parentheses

2m-(4(m+1)-18)-38=0



We calculate terms in parentheses: -(4(m+1)-18), so:

4(m+1)-18

We multiply parentheses

4m+4-18

We add all the numbers together, and all the variables

4m-14

Back to the equation:

-(4m-14)



We get rid of parentheses

2m-4m+14-38=0

We add all the numbers together, and all the variables

-2m-24=0

We move all terms containing m to the left, all other terms to the right

-2m=24

m=24/-2

m=-12

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