2(m-10)=13-3(2m+1)

Solution for 2(m-10)=13-3(2m+1) equation:

2(m-10)=13-3(2m+1)

We move all terms to the left:

2(m-10)-(13-3(2m+1))=0

We multiply parentheses

2m-(13-3(2m+1))-20=0


We calculate terms in parentheses: -(13-3(2m+1)), so:

13-3(2m+1)

determiningTheFunctionDomain
-3(2m+1)+13

We multiply parentheses

-6m-3+13

We add all the numbers together, and all the variables

-6m+10

Back to the equation:

-(-6m+10)


We get rid of parentheses

2m+6m-10-20=0

We add all the numbers together, and all the variables

8m-30=0

We move all terms containing m to the left, all other terms to the right

8m=30

m=30/8

m=3+3/4