2(m+7)-4(m+3)=15(m-1)

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Solution for 2(m+7)-4(m+3)=15(m-1) equation: 



2(m+7)-4(m+3)=15(m-1)

We move all terms to the left:

2(m+7)-4(m+3)-(15(m-1))=0

We multiply parentheses

2m-4m-(15(m-1))+14-12=0



We calculate terms in parentheses: -(15(m-1)), so:

15(m-1)

We multiply parentheses

15m-15

Back to the equation:

-(15m-15)



We add all the numbers together, and all the variables

-2m-(15m-15)+2=0

We get rid of parentheses

-2m-15m+15+2=0

We add all the numbers together, and all the variables

-17m+17=0

We move all terms containing m to the left, all other terms to the right

-17m=-17

m=-17/-17

m=1

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