2(m+40)-6m=3(4m-80)

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Solution for 2(m+40)-6m=3(4m-80) equation: 



2(m+40)-6m=3(4m-80)

We move all terms to the left:

2(m+40)-6m-(3(4m-80))=0

We add all the numbers together, and all the variables

-6m+2(m+40)-(3(4m-80))=0

We multiply parentheses

-6m+2m-(3(4m-80))+80=0



We calculate terms in parentheses: -(3(4m-80)), so:

3(4m-80)

We multiply parentheses

12m-240

Back to the equation:

-(12m-240)



We add all the numbers together, and all the variables

-4m-(12m-240)+80=0

We get rid of parentheses

-4m-12m+240+80=0

We add all the numbers together, and all the variables

-16m+320=0

We move all terms containing m to the left, all other terms to the right

-16m=-320

m=-320/-16

m=+20

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