2(m+4)+2=10-2(m-2)

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Solution for 2(m+4)+2=10-2(m-2) equation: 



2(m+4)+2=10-2(m-2)

We move all terms to the left:

2(m+4)+2-(10-2(m-2))=0

We multiply parentheses

2m-(10-2(m-2))+8+2=0



We calculate terms in parentheses: -(10-2(m-2)), so:

10-2(m-2)

determiningTheFunctionDomain
-2(m-2)+10

We multiply parentheses

-2m+4+10

We add all the numbers together, and all the variables

-2m+14

Back to the equation:

-(-2m+14)



We add all the numbers together, and all the variables

2m-(-2m+14)+10=0

We get rid of parentheses

2m+2m-14+10=0

We add all the numbers together, and all the variables

4m-4=0

We move all terms containing m to the left, all other terms to the right

4m=4

m=4/4

m=1

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