2(m+3/2)=2(m-5

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Solution for 2(m+3/2)=2(m-5 equation: 



2(m+3/2)=2(m-5

We move all terms to the left:

2(m+3/2)-(2(m-5)=0

We add all the numbers together, and all the variables

2(+m+3/2)-(2(m-5)=0

We multiply parentheses

2m-(2(m-5)+3/2*2=0

We multiply all the terms by the denominator


2m*2*2-(2(m-5)+3=0

Wy multiply elements

8m*2-(2(m-5)+3=0

Wy multiply elements

16m-(2(m-5)+3=0

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