2(m+3)=4(m-5)

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Solution for 2(m+3)=4(m-5) equation: 



2(m+3)=4(m-5)

We move all terms to the left:

2(m+3)-(4(m-5))=0

We multiply parentheses

2m-(4(m-5))+6=0



We calculate terms in parentheses: -(4(m-5)), so:

4(m-5)

We multiply parentheses

4m-20

Back to the equation:

-(4m-20)



We get rid of parentheses

2m-4m+20+6=0

We add all the numbers together, and all the variables

-2m+26=0

We move all terms containing m to the left, all other terms to the right

-2m=-26

m=-26/-2

m=+13

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