2(m+3)-5(m-4)=41

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Solution for 2(m+3)-5(m-4)=41 equation:


Simplifying
2(m + 3) + -5(m + -4) = 41

Reorder the terms:
2(3 + m) + -5(m + -4) = 41
(3 * 2 + m * 2) + -5(m + -4) = 41
(6 + 2m) + -5(m + -4) = 41

Reorder the terms:
6 + 2m + -5(-4 + m) = 41
6 + 2m + (-4 * -5 + m * -5) = 41
6 + 2m + (20 + -5m) = 41

Reorder the terms:
6 + 20 + 2m + -5m = 41

Combine like terms: 6 + 20 = 26
26 + 2m + -5m = 41

Combine like terms: 2m + -5m = -3m
26 + -3m = 41

Solving
26 + -3m = 41

Solving for variable 'm'.

Move all terms containing m to the left, all other terms to the right.

Add '-26' to each side of the equation.
26 + -26 + -3m = 41 + -26

Combine like terms: 26 + -26 = 0
0 + -3m = 41 + -26
-3m = 41 + -26

Combine like terms: 41 + -26 = 15
-3m = 15

Divide each side by '-3'.
m = -5

Simplifying
m = -5

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