2(m+3)+3(m-2)=4m+17

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Solution for 2(m+3)+3(m-2)=4m+17 equation:


Simplifying
2(m + 3) + 3(m + -2) = 4m + 17

Reorder the terms:
2(3 + m) + 3(m + -2) = 4m + 17
(3 * 2 + m * 2) + 3(m + -2) = 4m + 17
(6 + 2m) + 3(m + -2) = 4m + 17

Reorder the terms:
6 + 2m + 3(-2 + m) = 4m + 17
6 + 2m + (-2 * 3 + m * 3) = 4m + 17
6 + 2m + (-6 + 3m) = 4m + 17

Reorder the terms:
6 + -6 + 2m + 3m = 4m + 17

Combine like terms: 6 + -6 = 0
0 + 2m + 3m = 4m + 17
2m + 3m = 4m + 17

Combine like terms: 2m + 3m = 5m
5m = 4m + 17

Reorder the terms:
5m = 17 + 4m

Solving
5m = 17 + 4m

Solving for variable 'm'.

Move all terms containing m to the left, all other terms to the right.

Add '-4m' to each side of the equation.
5m + -4m = 17 + 4m + -4m

Combine like terms: 5m + -4m = 1m
1m = 17 + 4m + -4m

Combine like terms: 4m + -4m = 0
1m = 17 + 0
1m = 17

Divide each side by '1'.
m = 17

Simplifying
m = 17

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