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2(k-9)=50-3(10k+1)
We move all terms to the left:
2(k-9)-(50-3(10k+1))=0
We multiply parentheses
2k-(50-3(10k+1))-18=0
We calculate terms in parentheses: -(50-3(10k+1)), so:We get rid of parentheses
50-3(10k+1)
determiningTheFunctionDomain -3(10k+1)+50
We multiply parentheses
-30k-3+50
We add all the numbers together, and all the variables
-30k+47
Back to the equation:
-(-30k+47)
2k+30k-47-18=0
We add all the numbers together, and all the variables
32k-65=0
We move all terms containing k to the left, all other terms to the right
32k=65
k=65/32
k=2+1/32
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