2(k-6)+k=3k-12

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Solution for 2(k-6)+k=3k-12 equation:


Simplifying
2(k + -6) + k = 3k + -12

Reorder the terms:
2(-6 + k) + k = 3k + -12
(-6 * 2 + k * 2) + k = 3k + -12
(-12 + 2k) + k = 3k + -12

Combine like terms: 2k + k = 3k
-12 + 3k = 3k + -12

Reorder the terms:
-12 + 3k = -12 + 3k

Add '12' to each side of the equation.
-12 + 12 + 3k = -12 + 12 + 3k

Combine like terms: -12 + 12 = 0
0 + 3k = -12 + 12 + 3k
3k = -12 + 12 + 3k

Combine like terms: -12 + 12 = 0
3k = 0 + 3k
3k = 3k

Add '-3k' to each side of the equation.
3k + -3k = 3k + -3k

Combine like terms: 3k + -3k = 0
0 = 3k + -3k

Combine like terms: 3k + -3k = 0
0 = 0

Solving
0 = 0

Couldn't find a variable to solve for.

This equation is an identity, all real numbers are solutions.

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