2(k-4)=3k+6

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Solution for 2(k-4)=3k+6 equation: 



2(k-4)=3k+6

We move all terms to the left:

2(k-4)-(3k+6)=0

We multiply parentheses

2k-(3k+6)-8=0

We get rid of parentheses

2k-3k-6-8=0

We add all the numbers together, and all the variables

-1k-14=0

We move all terms containing k to the left, all other terms to the right

-k=14

k=14/-1

k=-14

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