2(k-3)=6+3k-3=

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Solution for 2(k-3)=6+3k-3= equation: 



2(k-3)=6+3k-3=

We move all terms to the left:

2(k-3)-(6+3k-3)=0

We add all the numbers together, and all the variables

2(k-3)-(3k+3)=0

We multiply parentheses

2k-(3k+3)-6=0

We get rid of parentheses

2k-3k-3-6=0

We add all the numbers together, and all the variables

-1k-9=0

We move all terms containing k to the left, all other terms to the right

-k=9

k=9/-1

k=-9

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