2(k-3)+3(2k-5)=11

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Solution for 2(k-3)+3(2k-5)=11 equation:


Simplifying
2(k + -3) + 3(2k + -5) = 11

Reorder the terms:
2(-3 + k) + 3(2k + -5) = 11
(-3 * 2 + k * 2) + 3(2k + -5) = 11
(-6 + 2k) + 3(2k + -5) = 11

Reorder the terms:
-6 + 2k + 3(-5 + 2k) = 11
-6 + 2k + (-5 * 3 + 2k * 3) = 11
-6 + 2k + (-15 + 6k) = 11

Reorder the terms:
-6 + -15 + 2k + 6k = 11

Combine like terms: -6 + -15 = -21
-21 + 2k + 6k = 11

Combine like terms: 2k + 6k = 8k
-21 + 8k = 11

Solving
-21 + 8k = 11

Solving for variable 'k'.

Move all terms containing k to the left, all other terms to the right.

Add '21' to each side of the equation.
-21 + 21 + 8k = 11 + 21

Combine like terms: -21 + 21 = 0
0 + 8k = 11 + 21
8k = 11 + 21

Combine like terms: 11 + 21 = 32
8k = 32

Divide each side by '8'.
k = 4

Simplifying
k = 4

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