2(k+9)-6(3k+12)=5(2k+3)+3(k-3)

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Solution for 2(k+9)-6(3k+12)=5(2k+3)+3(k-3) equation: 



2(k+9)-6(3k+12)=5(2k+3)+3(k-3)

We move all terms to the left:

2(k+9)-6(3k+12)-(5(2k+3)+3(k-3))=0

We multiply parentheses

2k-18k-(5(2k+3)+3(k-3))+18-72=0



We calculate terms in parentheses: -(5(2k+3)+3(k-3)), so:

5(2k+3)+3(k-3)

We multiply parentheses

10k+3k+15-9

We add all the numbers together, and all the variables

13k+6

Back to the equation:

-(13k+6)



We add all the numbers together, and all the variables

-16k-(13k+6)-54=0

We get rid of parentheses

-16k-13k-6-54=0

We add all the numbers together, and all the variables

-29k-60=0

We move all terms containing k to the left, all other terms to the right

-29k=60

k=60/-29

k=-2+2/29

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