2(k+2)-5=3(k+1)

Solution for 2(k+2)-5=3(k+1) equation:

2(k+2)-5=3(k+1)

We move all terms to the left:

2(k+2)-5-(3(k+1))=0

We multiply parentheses

2k-(3(k+1))+4-5=0


We calculate terms in parentheses: -(3(k+1)), so:

3(k+1)

We multiply parentheses

3k+3

Back to the equation:

-(3k+3)


We add all the numbers together, and all the variables

2k-(3k+3)-1=0

We get rid of parentheses

2k-3k-3-1=0

We add all the numbers together, and all the variables

-1k-4=0

We move all terms containing k to the left, all other terms to the right

-k=4

k=4/-1

k=-4