2(j-8)+7=5(j+2)-3j-19

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Solution for 2(j-8)+7=5(j+2)-3j-19 equation:


Simplifying
2(j + -8) + 7 = 5(j + 2) + -3j + -19

Reorder the terms:
2(-8 + j) + 7 = 5(j + 2) + -3j + -19
(-8 * 2 + j * 2) + 7 = 5(j + 2) + -3j + -19
(-16 + 2j) + 7 = 5(j + 2) + -3j + -19

Reorder the terms:
-16 + 7 + 2j = 5(j + 2) + -3j + -19

Combine like terms: -16 + 7 = -9
-9 + 2j = 5(j + 2) + -3j + -19

Reorder the terms:
-9 + 2j = 5(2 + j) + -3j + -19
-9 + 2j = (2 * 5 + j * 5) + -3j + -19
-9 + 2j = (10 + 5j) + -3j + -19

Reorder the terms:
-9 + 2j = 10 + -19 + 5j + -3j

Combine like terms: 10 + -19 = -9
-9 + 2j = -9 + 5j + -3j

Combine like terms: 5j + -3j = 2j
-9 + 2j = -9 + 2j

Add '9' to each side of the equation.
-9 + 9 + 2j = -9 + 9 + 2j

Combine like terms: -9 + 9 = 0
0 + 2j = -9 + 9 + 2j
2j = -9 + 9 + 2j

Combine like terms: -9 + 9 = 0
2j = 0 + 2j
2j = 2j

Add '-2j' to each side of the equation.
2j + -2j = 2j + -2j

Combine like terms: 2j + -2j = 0
0 = 2j + -2j

Combine like terms: 2j + -2j = 0
0 = 0

Solving
0 = 0

Couldn't find a variable to solve for.

This equation is an identity, all real numbers are solutions.

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