2(j-4)=2(3j-10)

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Solution for 2(j-4)=2(3j-10) equation: 



2(j-4)=2(3j-10)

We move all terms to the left:

2(j-4)-(2(3j-10))=0

We multiply parentheses

2j-(2(3j-10))-8=0



We calculate terms in parentheses: -(2(3j-10)), so:

2(3j-10)

We multiply parentheses

6j-20

Back to the equation:

-(6j-20)



We get rid of parentheses

2j-6j+20-8=0

We add all the numbers together, and all the variables

-4j+12=0

We move all terms containing j to the left, all other terms to the right

-4j=-12

j=-12/-4

j=+3

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