2(i+5)=3(i-4)

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Solution for 2(i+5)=3(i-4) equation: 



2(i+5)=3(i-4)

We move all terms to the left:

2(i+5)-(3(i-4))=0

We multiply parentheses

2i-(3(i-4))+10=0



We calculate terms in parentheses: -(3(i-4)), so:

3(i-4)

We multiply parentheses

3i-12

Back to the equation:

-(3i-12)



We get rid of parentheses

2i-3i+12+10=0

We add all the numbers together, and all the variables

-1i+22=0

We move all terms containing i to the left, all other terms to the right

-i=-22

i=-22/-1

i=+22

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