2(h-3)=4(h+10)

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Solution for 2(h-3)=4(h+10) equation: 



2(h-3)=4(h+10)

We move all terms to the left:

2(h-3)-(4(h+10))=0

We multiply parentheses

2h-(4(h+10))-6=0



We calculate terms in parentheses: -(4(h+10)), so:

4(h+10)

We multiply parentheses

4h+40

Back to the equation:

-(4h+40)



We get rid of parentheses

2h-4h-40-6=0

We add all the numbers together, and all the variables

-2h-46=0

We move all terms containing h to the left, all other terms to the right

-2h=46

h=46/-2

h=-23

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