2(h-3)=1/7(7h+28)

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Solution for 2(h-3)=1/7(7h+28) equation: 



2(h-3)=1/7(7h+28)

We move all terms to the left:

2(h-3)-(1/7(7h+28))=0



Domain of the equation: 7(7h+28))!=0

h∈R



We multiply parentheses

2h-(1/7(7h+28))-6=0

We multiply all the terms by the denominator


2h*7(7h+28))-(1-6*7(7h+28))=0

Wy multiply elements

14h^2(7-42h(7=0

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