2(h+1)=5(h-7)

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Solution for 2(h+1)=5(h-7) equation:



2(h+1)=5(h-7)
We move all terms to the left:
2(h+1)-(5(h-7))=0
We multiply parentheses
2h-(5(h-7))+2=0
We calculate terms in parentheses: -(5(h-7)), so:
5(h-7)
We multiply parentheses
5h-35
Back to the equation:
-(5h-35)
We get rid of parentheses
2h-5h+35+2=0
We add all the numbers together, and all the variables
-3h+37=0
We move all terms containing h to the left, all other terms to the right
-3h=-37
h=-37/-3
h=12+1/3

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