2(h+1)=3(2h-6)

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Solution for 2(h+1)=3(2h-6) equation: 



2(h+1)=3(2h-6)

We move all terms to the left:

2(h+1)-(3(2h-6))=0

We multiply parentheses

2h-(3(2h-6))+2=0



We calculate terms in parentheses: -(3(2h-6)), so:

3(2h-6)

We multiply parentheses

6h-18

Back to the equation:

-(6h-18)



We get rid of parentheses

2h-6h+18+2=0

We add all the numbers together, and all the variables

-4h+20=0

We move all terms containing h to the left, all other terms to the right

-4h=-20

h=-20/-4

h=+5

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