2(f-3)=2(f-2)-5

Solution for 2(f-3)=2(f-2)-5 equation:

Simplifying
2(f + -3) = 2(f + -2) + -5

Reorder the terms:
2(-3 + f) = 2(f + -2) + -5
(-3 * 2 + f * 2) = 2(f + -2) + -5
(-6 + 2f) = 2(f + -2) + -5

Reorder the terms:
-6 + 2f = 2(-2 + f) + -5
-6 + 2f = (-2 * 2 + f * 2) + -5
-6 + 2f = (-4 + 2f) + -5

Reorder the terms:
-6 + 2f = -4 + -5 + 2f

Combine like terms: -4 + -5 = -9
-6 + 2f = -9 + 2f

Add '-2f' to each side of the equation.
-6 + 2f + -2f = -9 + 2f + -2f

Combine like terms: 2f + -2f = 0
-6 + 0 = -9 + 2f + -2f
-6 = -9 + 2f + -2f

Combine like terms: 2f + -2f = 0
-6 = -9 + 0
-6 = -9

Solving
-6 = -9

Couldn't find a variable to solve for.

This equation is invalid, the left and right sides are not equal, therefore there is no solution.